一、遍歷文件夾下所有文件，輸出文件名
復制代碼 代碼如下:
def traverse_dir(file_path)
if File.directory? file_path
Dir.foreach(file_path) do |file|
if file !="." and file !=".."
traverse_dir(file_path+"/"+file)
end
end
else
puts "File:#{File.basename(file_path)}, Size:#{File.size(file_path)}"
end
end
traverse_dir('D:/apache-tomcat')
二、ruby遍歷文件夾
復制代碼 代碼如下:
def get_file_list(path)
Dir.entries(path).each do |sub|
if sub != '.' sub != '..'
if File.directory?("#{path}/#{sub}")
puts "[#{sub}]"
get_file_list("#{path}/#{sub}")
else
puts " |--#{sub}"
end
end
end
end
三、python如何遍歷一個目錄輸出所有文件名
復制代碼 代碼如下:
#coding=utf-8
'''
Created on 2014-11-14
@author: Neo
'''
import os
def GetFileList(dir, fileList):
newDir = dir
if os.path.isfile(dir):
fileList.append(dir.decode('gbk'))
elif os.path.isdir(dir):
for s in os.listdir(dir):
#如果需要忽略某些文件夾，使用以下代碼
#if s == "xxx":
#continue
newDir=os.path.join(dir,s)
GetFileList(newDir, fileList)
return fileList
list = GetFileList('D:\\workspace\\PyDemo\\fas', [])
for e in list:
print e
result:
復制代碼 代碼如下:
D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1100.log
D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1101.log
D:\workspace\PyDemo\fas\file1\20141113\a.20141113-1140.log
D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1100.log
D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1101.log
D:\workspace\PyDemo\fas\file2\20141113\a.20141113-1140.log
四、簡潔遍歷寫法
復制代碼 代碼如下:
import os
def iterbrowse(path):
for home, dirs, files in os.walk(path):
for filename in files:
yield os.path.join(home, filename)
for fullname in iterbrowse("/home/bruce"):
print fullname
